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4500=50/x^2
We move all terms to the left:
4500-(50/x^2)=0
Domain of the equation: x^2)!=0We get rid of parentheses
x!=0/1
x!=0
x∈R
-50/x^2+4500=0
We multiply all the terms by the denominator
4500*x^2-50=0
We add all the numbers together, and all the variables
4500x^2-50=0
a = 4500; b = 0; c = -50;
Δ = b2-4ac
Δ = 02-4·4500·(-50)
Δ = 900000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{900000}=\sqrt{90000*10}=\sqrt{90000}*\sqrt{10}=300\sqrt{10}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-300\sqrt{10}}{2*4500}=\frac{0-300\sqrt{10}}{9000} =-\frac{300\sqrt{10}}{9000} =-\frac{\sqrt{10}}{30} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+300\sqrt{10}}{2*4500}=\frac{0+300\sqrt{10}}{9000} =\frac{300\sqrt{10}}{9000} =\frac{\sqrt{10}}{30} $
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